on aura des équations de la forme suivante
dans lesquelles on aura les valeurs suivantes des quantités ( H ) , ( h ) , ( A ) , ( a ) , … {\displaystyle (\mathrm {H} ),(h),(\mathrm {A} ),(a),\ldots }
![{\displaystyle {\begin{aligned}d\,\delta h=&{\frac {\mu }{1+m}}\left[(\mathrm {H} )\Pi +(h)\varpi \right]du,\\d\,\delta a=&{\frac {\mu }{1+m}}\left[(\mathrm {A} )\Pi +(a)\varpi \right]du,\\d\,\delta f=&{\frac {\mu }{1+m}}\left[(\mathrm {F} )\Pi +(f)\varpi \right]du,\\d\,\delta g=&{\frac {\mu }{1+m}}\left[(\mathrm {G} )\Pi +(g)\varpi \right]du,\\d\,\delta b=&{\frac {\mu }{1+m}}\left[(\mathrm {B} )\Pi +(b)\varpi \right]du,\\d\,\delta c=&{\frac {\mu }{1+m}}\left[(\mathrm {C} )\Pi +(c)\varpi \right]du,\\d\,\delta i=&{\frac {\mu }{1+m}}\left[(\mathrm {I} )\ \,\Pi +(i)\varpi \right]du,\\\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/456c688a373324a90b34e08ac0d6dd1d8fbde5bd)
![{\displaystyle {\begin{aligned}(\mathrm {H} )=&{\sqrt {ah}}(y\xi -x\eta )r,\quad (h)=0,\\(\mathrm {A} )=&a^{2}\left({\frac {a}{2}}\xi \sin u-{\sqrt {ah}}\,\eta \cos u\right),\quad (a)=-{\frac {a^{2}f}{2}}r\sin u,\\(\mathrm {F} )=&-{\sqrt {\frac {a}{4h}}}\left[(fr+x)\xi +y\eta \right]y+2{\sqrt {ah}}(y\xi -x\eta )\cos u,\ \ (f)=-{\sqrt {ah}}\,ry,\\(\mathrm {G} )=&{\sqrt {\frac {a}{4h}}}\left[(fr+x)\xi +y\eta \right]x+a(y\xi -x\eta )\sin u,\quad (g)={\sqrt {ah}}rx,\\(\mathrm {B} )=&{\sqrt {\frac {a}{4h}}}ry\zeta ,\quad (b)=0,\\(\mathrm {C} )=&-{\sqrt {\frac {a}{4h}}}rx\zeta ,\quad (c)=0,\\(\mathrm {I} )=&3t{\sqrt {\frac {2(1+m)}{a^{5}}}}(\mathrm {A} )-{\frac {2r^{2}(\mathrm {G} )}{f{\sqrt {a^{3}h}}}}+{\frac {y(fx-4h)}{2{\sqrt {ah^{3}}}}}(\mathrm {F} ),\\(i)=&3t{\sqrt {\frac {2(1+m)}{a^{5}}}}(a)\ \,-{\frac {2r^{2}(g)}{f{\sqrt {a^{3}h}}}}+{\frac {y(fx-4h)}{2{\sqrt {ah^{3}}}}}(f).\end{aligned}}}](https://wikimedia.org/api/rest_v1/media/math/render/svg/6d2080b8fefaa79c9049672b5fcbb5d0a747dd36)
